*Updated at 3:17PM EST to reflect the compensatory pick report.
It has been reported via Ian Rapoport that the 49ers have signed away Buccaneers LB Kwon Alexander.
Source: The #49ers are signing LB Kwon Alexander to a 4-year deal worth $54M.
— Ian Rapoport (@RapSheet) March 11, 2019
It is a 4 year deal worth $54 million. Which is $13.5 million per year on average. With $27 million in guarantees.
This move comes on the heels of a report that Alexander was to test free agency despite a $10 million per year offer from the Buccaneers.
It was also speculated that Alexander’s price tag may not been as high as originally expected. Well those rumors were put to rest with the a big contract from San Francisco.
Now the Bucs officially have a hole at linebacker. Especially with the pending future health of LB Kendall Beckwith. The Bucs could likely look into free agency or the draft to fill that void.
About the Kwon Alexander report: #Bucs are in position to get a decent compensatory pick in 2020, though they could cancel that out. https://t.co/QxnrOeCa34
— Thomas Bassinger (@tometrics) March 11, 2019
In return though, the Bucs could received a decent compensatory pick in 2020 Fted the Alexander departure.
Stay tuned as updates are available.
